2013-01-10, 04:12 PM
math and you just don't go together xDD
My alternate method- (too complicated for some people)
Let a the first jail time, let b be the second jail time, let c be the normal jail time for the second jail, let x be the normal 3rd jail time and y be the ban time.
a+c=b
2(a+b+x)=y
So someone griefs. (small)
a= 1 hour
The they home kill WITHIN a week
Homekill would be an hour.
We need to find b
and a+c=b
Plug it in.
1 hour+ 1 hour= 2 hours
That will be the second jail time.
If they are jailed again WITHIN one week of the SECOND jail,
we need to find
2(a+b+x)=y
Lets say they grief a lot, and are jailed for a day.
That is x
a=1 hour
b=1 hour
x=1 day
1 hour + 1 hour + 1 day * 2 = y
1 day, 2 hours *2 = y
2 days, 4 hours = y
y = ban time
So they'd be banned for 2 days, and four hours.
It is a simple formula, once you get it.
I can turn ANYTHING into an equation.
My alternate method- (too complicated for some people)
Let a the first jail time, let b be the second jail time, let c be the normal jail time for the second jail, let x be the normal 3rd jail time and y be the ban time.
a+c=b
2(a+b+x)=y
So someone griefs. (small)
a= 1 hour
The they home kill WITHIN a week
Homekill would be an hour.
We need to find b
and a+c=b
Plug it in.
1 hour+ 1 hour= 2 hours
That will be the second jail time.
If they are jailed again WITHIN one week of the SECOND jail,
we need to find
2(a+b+x)=y
Lets say they grief a lot, and are jailed for a day.
That is x
a=1 hour
b=1 hour
x=1 day
1 hour + 1 hour + 1 day * 2 = y
1 day, 2 hours *2 = y
2 days, 4 hours = y
y = ban time
So they'd be banned for 2 days, and four hours.
It is a simple formula, once you get it.
I can turn ANYTHING into an equation.
GOODBYE